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Fig. 1. A model of how stopping ability and total travel distance could constrain
modulation of velocity during a start and stop. The hypothetical movements in
A and B have identical starting accelerations
(astart=slope=1) and total displacements
(Stotal=areas under the triangles or trapezoids with a
vertex indicated by a circle=3 units), but the stopping acceleration
(astop) varies among the cases indicated by the different
colors within each panel. (A) Starting acceleration continues up to the
instant when stopping begins (indicated by circles). Compared to
astop=1, increased stopping ability (green) allows more
distance to accelerate to a greater maximal velocity
(Vmax), which decreases total travel time. Decreased
stopping ability (red) has detrimental effects on Vmax and
total travel time. Consequently, the average velocities
(Stotal divided by total time) for
astop=2 and 0.5 are 115% and 81% of the value when
astop=1, respectively. (B) When the total distance provides
sufficient time so that a physiologically maximum speed is attained and
momentarily sustained, stopping ability will not affect
Vmax. However, increased stopping ability decreases total
time and hence the average velocities for astop=2 and 0.5
are 107% and 89% of the value when astop=1, respectively.
Maintaining a constant velocity in between the starting and stopping
accelerations (B) increases total travel time and hence decreases average
velocity compared to beginning a stop immediately after the cessation of a
starting acceleration (compare A vs B for equal values of
astart and astop). If the only objective
of starting and stopping is to minimize total travel time (and maximize
average speed) for a given distance, then maximal accelerating and
decelerating capacities should be used. (C) For a linear increase in velocity
followed immediately by a linear decrease in velocity as in A,
Vmax=astart[(2Stotal)/(astart+1/astop)]0.5
and hence the upper limit of Vmax is
astart0.5(2Stotal)0.5.
Axes show arbitrary units.